Question

In a hypothetical fission reaction
\(^{92}X^{236} \rightarrow ^{56}Y^{141} + ^{36}Z^{92} + 3R\) The identity of emitted particles (R) is:

• A. Proton
• B. Electron
• C. Neutron
• D. \(\gamma\)-radiations

Answer 1

The Correct Option is C

To identify the emitted particles, let us verify the conservation of atomic number (\(Z\)) and mass number (\(A\)).

- Atomic number (\(Z\)):

\[ Z_{\text{LHS}} = 92, \quad Z_{\text{RHS}} = 56 + 36 = 92 \]

\(Z\) is conserved.

- Mass number (\(A\)):

\[ A_{\text{LHS}} = 236, \quad A_{\text{RHS}} = 141 + 92 = 233 \]

The mass number is not conserved. The difference is:

\[ A_{\text{LHS}} - A_{\text{RHS}} = 236 - 233 = 3 \]

The missing mass corresponds to three neutrons (\(R = \text{neutrons}\)).