Given, $\frac{x^{2}}{36} - \frac{y^{2}}{k^{2}} = 1$
$ \Rightarrow \frac{y^{2}}{k^{2}} = \frac{x^{2}}{36} -1 $
$ \Rightarrow k^{2} = \frac{36 y^{2}}{x^{2} -36}$
$ k^{2} >\,0$
If $ x^{2} - 36 > \,0 $
$ \Rightarrow x^{2} >\, 36 $
This is true only for point $(10, 4)$ So, $(10, 4)$ lies on the hyperbola