Question:

If \( \triangle ABC \) has \( AB = 13 \) cm, \( BC = 12 \) cm, and \( AC = 5 \) cm, then \( \angle C \) is:

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A triangle is a right-angled triangle if it satisfies the Pythagorean theorem: [\ c^2 = a^2 + b^2. \]
Updated On: Oct 27, 2025
  • \( 90^\circ \)
  • \( 30^\circ \)
  • \( 60^\circ \)
  • \( 45^\circ \)
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The Correct Option is A

Solution and Explanation

Using the Pythagorean theorem:
[\ AB^2 = AC^2 + BC^2. 13^2 = 5^2 + 12^2. \] 169 = 25 + 1 \[ 169 = 1 \] Since the equation holds, \( \triangle ABC \) is a right triangle with \( \angle C = 90^\circ \).
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