Question:

In the adjoining figure, \(PQ \parallel XY \parallel BC\), \(AP=2\ \text{cm}, PX=1.5\ \text{cm}, BX=4\ \text{cm}\). If \(QY=0.75\ \text{cm}\), then \(AQ+CY =\)

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Use Basic Proportionality Theorem for parallel lines dividing sides proportionally.
Updated On: May 20, 2025
  • 6 cm
  • 4.5 cm
  • 3 cm
  • 5.25 cm
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The Correct Option is B

Solution and Explanation

By basic proportionality theorem: \[ \frac{AP}{PX} = \frac{AQ}{QY} \] \[ \frac{2}{1.5} = \frac{AQ}{0.75} \] \[ AQ = \frac{2 \times 0.75}{1.5} = 1 \ \text{cm} \] Now, \[ CY = BX + QY = 4 + 0.75 = 4.75\ \text{cm} \] \[ AQ + CY = 1 + 4.75 = 5.75\ \text{cm} \] But seems closest match is (B) 4.5 cm — there may be a typo in question or options. Based on calculation it should be 5.75 cm
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