To solve the problem, we need to analyze the expression given in the question step by step.
Step 1: Represent z
Given that Re(z)=3, we can represent z as: z=3+iy where y is the imaginary part of z.
Step 2: Compute z̄
The conjugate of z is: z̄=3−iy
Step 3: Substitute z and z̄ into the expression
We need to compute: Re(z−z̄+zz̄2−3z+5z̄)
First, calculate z−z̄: z−z̄=(3+iy)−(3−iy)=2iy
Next, calculate zz̄: zz̄=(3+iy)(3−iy)=9+y2
Step 4: Calculate the numerator
Now, the numerator becomes: z−z̄+zz̄=2iy+(9+y2)=9+y2+2iy
Step 5: Calculate the denominator
Now, calculate the denominator: 2−3z+5z̄=2−3(3+iy)+5(3−iy)=2−9−3iy+15−5iy=8−8iy
Step 6: Form the complete expression
Now, we can write the complete expression: 9+y2+2iy8−8iy
Step 7: Rationalize the denominator
To find the real part, we multiply the numerator and denominator by the conjugate of the denominator: (9+y2+2iy)(8+8iy)(8−8iy)(8+8iy)
The denominator simplifies to: 64+64y2
The numerator expands to: (9+y2)8+(9+y2)(8iy)+2iy(8)+2iy(8iy)
This results in: 72+8y2+72iy+16iy−16y=72+8y2−16y+(72+16)iy
Step 8: Extract the real part
The real part of the expression is: 72+8y2−16y64+64y2
Step 9: Set the real part to find the interval
To find the interval for t=72+8y2−16y64+64y2, we need to ensure that the expression is non-negative: 72+8y2−16y≥0
This is a quadratic inequality in y.
Step 10: Solve the quadratic inequality
The roots of 8y2−16y+72=0 can be found using the quadratic formula: y=−b±√b2−4ac2a=16±√(−16)2−4⋅8⋅722⋅8
Calculating the discriminant: 256−2304=−2048
Since the discriminant is negative, the quadratic does not cross the x-axis and is always positive.
Step 11: Find the bounds of t
Now, we find the bounds of t: t∈(−18,98)
Step 12: Calculate 24(β−α)
Here, α=−18 and β=98: β−α=98+18=108=54
Thus, 24(β−α)=24⋅54=30
Final Answer
The value of 24(β−α) is 30