To solve the problem, we need to analyze the expression given in the question step by step.
Step 1: Represent z
Given that Re(z)=3, we can represent z as: z=3+iy where y is the imaginary part of z.
Step 2: Compute z̄
The conjugate of z is: z̄=3−iy
Step 3: Substitute z and z̄ into the expression
We need to compute: Re(z−z̄+zz̄2−3z+5z̄)
First, calculate z−z̄: z−z̄=(3+iy)−(3−iy)=2iy
Next, calculate zz̄: zz̄=(3+iy)(3−iy)=9+y2
Step 4: Calculate the numerator
Now, the numerator becomes: z−z̄+zz̄=2iy+(9+y2)=9+y2+2iy
Step 5: Calculate the denominator
Now, calculate the denominator: 2−3z+5z̄=2−3(3+iy)+5(3−iy)=2−9−3iy+15−5iy=8−8iy
Step 6: Form the complete expression
Now, we can write the complete expression: 9+y2+2iy8−8iy
Step 7: Rationalize the denominator
To find the real part, we multiply the numerator and denominator by the conjugate of the denominator: (9+y2+2iy)(8+8iy)(8−8iy)(8+8iy)
The denominator simplifies to: 64+64y2
The numerator expands to: (9+y2)8+(9+y2)(8iy)+2iy(8)+2iy(8iy)
This results in: 72+8y2+72iy+16iy−16y=72+8y2−16y+(72+16)iy
Step 8: Extract the real part
The real part of the expression is: 72+8y2−16y64+64y2
Step 9: Set the real part to find the interval
To find the interval for t=72+8y2−16y64+64y2, we need to ensure that the expression is non-negative: 72+8y2−16y≥0
This is a quadratic inequality in y.
Step 10: Solve the quadratic inequality
The roots of 8y2−16y+72=0 can be found using the quadratic formula: y=−b±√b2−4ac2a=16±√(−16)2−4⋅8⋅722⋅8
Calculating the discriminant: 256−2304=−2048
Since the discriminant is negative, the quadratic does not cross the x-axis and is always positive.
Step 11: Find the bounds of t
Now, we find the bounds of t: t∈(−18,98)
Step 12: Calculate 24(β−α)
Here, α=−18 and β=98: β−α=98+18=108=54
Thus, 24(β−α)=24⋅54=30
Final Answer
The value of 24(β−α) is 30
Two circular discs of radius \(10\) cm each are joined at their centres by a rod, as shown in the figure. The length of the rod is \(30\) cm and its mass is \(600\) g. The mass of each disc is also \(600\) g. If the applied torque between the two discs is \(43\times10^{-7}\) dyne·cm, then the angular acceleration of the system about the given axis \(AB\) is ________ rad s\(^{-2}\).

Method used for separation of mixture of products (B and C) obtained in the following reaction is: 