Question

If the peak rectified voltage from a full-wave rectifier is 15V, the approximate average rectified voltage will be:

• A. \( 9.50 \) V
• B. \( 4.75 \) V
• C. \( \frac{15}{\sqrt{2}} \) V
• D. \( 15 \sqrt{2} \) V

Answer 1

The Correct Option is A

The relationship between the peak rectified voltage (\( V_{\text{peak}} \)) and the average rectified voltage (\( V_{\text{avg}} \)) for a full-wave rectifier is given by the following formula:

\(V_{\text{avg}} = \frac{2}{\pi} V_{\text{peak}}\)

Given that the peak rectified voltage is \( V_{\text{peak}} = 15V ,\) we can substitute this value into the formula to find the average rectified voltage:

\(V_{\text{avg}} = \frac{2}{\pi} \times 15 \approx 9.50 \, \text{V}\)

Conclusion: The approximate average rectified voltage for a full-wave rectifier with a peak rectified voltage of 15V is \( 9.50 \, \text{V} \).