The mean \( \mu \) and variance \( \sigma^2 \) of a binomial distribution are given by:
\[
\mu = np \quad \text{and} \quad \sigma^2 = np(1 - p)
\]
Using the given values \( \mu = 2.4 \) and \( \sigma^2 = 1.44 \), we solve for \( n \) and \( p \). The solution gives \( n = \frac{6}{5} \) and \( p = \frac{2}{5} \).