The mean lifetime \( \tau \) is related to the half-life \( t_{1/2} \) by the equation:
\[
\tau = \frac{t_{1/2}}{\ln(2)}
\]
Where:
- \( t_{1/2} \) is the half-life,
- \( \ln(2) \approx 0.693 \).
1. Step 1: Calculate the mean lifetime for \( D \):
\[
\tau_D = \frac{1500}{\ln(2)} = \frac{1500}{0.693} \approx 2164 \, \text{years}
\]
2. Step 2: Calculate the mean lifetime for \( B \):
\[
\tau_B = \frac{2000}{\ln(2)} = \frac{2000}{0.693} \approx 2887 \, \text{years}
\]
3. Step 3: Find the average of the mean lifetimes:
The mean lifetime is the average of \( \tau_D \) and \( \tau_B \):
\[
\tau = \frac{2164 + 2887}{2} \approx 1750 \, \text{years}
\]
Thus, the mean lifetime is approximately \( 1750 \) years.