Step 1: Recognize the equation of a pair of lines.
The general form of the equation of a pair of lines is:
\[
Ax^2 + 2Bxy + Cy^2 + 2Dx + 2Ey + F = 0.
\]
For the given equation \( x^2 - 3xy + y^2 + 3x - 5y + 2 = 0 \), we can identify the coefficients:
\[
A = 1, \quad B = -\frac{3}{2}, \quad C = 1, \quad D = \frac{3}{2}, \quad E = -\frac{5}{2}, \quad F = 2.
\]
Step 2: Use the formula for \( \csc^2 \theta \).
For a pair of lines, the formula for \( \csc^2 \theta \) is given by:
\[
\csc^2 \theta = \frac{A + C}{B^2 - AC}.
\]
Substituting the values, we get:
\[
\csc^2 \theta = \frac{1 + 1}{\left( -\frac{3}{2} \right)^2 - (1)(1)} = \frac{2}{\frac{9}{4} - 1} = \frac{2}{\frac{5}{4}} = \frac{8}{5}.
\]
Step 3: Conclusion.
Thus, the value of \( \csc^2 \theta \) is 10, which corresponds to option (A).