Question:

If the body cools from \( 135^\circ C \) to \( 80^\circ C \) at room temperature of \( 25^\circ C \) in 60 minutes, then the temperature of the body after 2 hours is

Show Hint

Use Newton’s Law of Cooling to model temperature changes over time. The constant \( k \) can be determined from the initial conditions.
Updated On: Jan 30, 2026
  • \( 52.5^\circ C \)
  • \( 10.5^\circ C \)
  • \( 52.75^\circ C \)
  • \( 10.75^\circ C \)
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Step 1: Apply Newton's Law of Cooling.
Newton’s Law of Cooling states that the rate of change of temperature of an object is proportional to the difference between the temperature of the object and the ambient temperature: \[ \frac{dT}{dt} = -k(T - T_{\text{room}}) \] where \( T_{\text{room}} = 25^\circ C \). The object cools from \( 135^\circ C \) to \( 80^\circ C \) in 60 minutes. Using this information, we can find the constant of proportionality \( k \).
Step 2: Solve for \( k \).
After solving for \( k \), we use the equation to determine the temperature after 2 hours.
Step 3: Conclusion.
The temperature after 2 hours is found to be \( 52.5^\circ C \), corresponding to option (A).
Was this answer helpful?
0
0

Top Questions on Differential equations

View More Questions