We are given that: \[ \tan^{-1}(x) = \tan^{-1}\left( 3 - \frac{\pi}{4} \right) \] Since \( \tan^{-1}(x) \) gives the angle whose tangent is \( x \), the above equation implies: \[ x = 3 - \frac{\pi}{4} \]
Thus, the value of \( x \) is \( 3 - \frac{\pi}{4} \).
Considering the principal values of the inverse trigonometric functions, $\sin^{-1} \left( \frac{\sqrt{3}}{2} x + \frac{1}{2} \sqrt{1-x^2} \right)$, $-\frac{1}{2}<x<\frac{1}{\sqrt{2}}$, is equal to
The following data were obtained for the reaction: \[ 2NO(g) + O_2(g) \rightarrow 2N_2O(g) \] at different concentrations:
The rate law of this reaction is: