Given set - \(\{1, 2, 3, 4\}\).
To form the smallest equivalence relation on this set that includes \((1, 2)\) and \((1, 3)\), we need to ensure that \(R\) is reflexive, symmetric, and transitive.
Step 1. Reflexive pairs: \((1, 1), (2, 2), (3, 3), (4, 4)\)
Step 2. Pairs to satisfy given conditions and transitivity:
- Since \((1, 2) \in R\) and \((1, 3) \in R\), we need \((2, 3) \in R\) for transitivity.
- For symmetry, include \((2, 1), (3, 1), (3, 2)\).
Step 3. Final set of pairs: \(R = \{(1, 1), (2, 2), (3, 3), (4, 4), (1, 2), (2, 1), (1, 3), (3, 1), (2, 3), (3, 2)\}\).
Thus, the number of elements in \(R\) is 10.
The Correct Answer is: 10
Let $P(S)$ denote the power set of $S=\{1,2,3, \ldots , 10\}$. Define the relations $R_1$ and $R_2$ on $P(S)$ as $A_1 B$ if $\left(A \cap B^c\right) \cup\left(B \cap A^c\right)=\emptyset$ and $A_2 B$ if $A \cup B^c=B \cup A^c, \forall A, B \in P(S)$. Then :
Let \(S=\){\(n∈NIn^3+3n^2+5n+3\) is not divisible by \(3\)}.Then, which of the following statements is true about \(S\)