To find the smallest equivalence relation \( R \) on the set \( \{1, 2, 3, 4\} \) that includes the pairs \( \{(1,2), (1,3)\} \), we have to ensure that \( R \) satisfies the properties of an equivalence relation: reflexivity, symmetry, and transitivity.
Step 1: Reflexivity
Step 2: Including Given Pairs and Ensuring Symmetry
Step 3: Ensuring Transitivity
Final Equivalence Relation \( R \)
Thus, the equivalence relation \( R \) contains 10 elements.
| Set of Pairs in \( R \) |
|---|
| (1,1), (2,2), (3,3), (4,4), (1,2), (2,1), (1,3), (3,1), (2,3), (3,2) |
Therefore, the number of elements in \( R \) is 10, which matches the correct answer.
Given set - \(\{1, 2, 3, 4\}\).
To form the smallest equivalence relation on this set that includes \((1, 2)\) and \((1, 3)\), we need to ensure that \(R\) is reflexive, symmetric, and transitive.
Step 1. Reflexive pairs: \((1, 1), (2, 2), (3, 3), (4, 4)\)
Step 2. Pairs to satisfy given conditions and transitivity:
- Since \((1, 2) \in R\) and \((1, 3) \in R\), we need \((2, 3) \in R\) for transitivity.
- For symmetry, include \((2, 1), (3, 1), (3, 2)\).
Step 3. Final set of pairs: \(R = \{(1, 1), (2, 2), (3, 3), (4, 4), (1, 2), (2, 1), (1, 3), (3, 1), (2, 3), (3, 2)\}\).
Thus, the number of elements in \(R\) is 10.
The Correct Answer is: 10
Consider the following sequence of reactions : 
Molar mass of the product formed (A) is ______ g mol\(^{-1}\).

In the first configuration (1) as shown in the figure, four identical charges \( q_0 \) are kept at the corners A, B, C and D of square of side length \( a \). In the second configuration (2), the same charges are shifted to mid points C, E, H, and F of the square. If \( K = \frac{1}{4\pi \epsilon_0} \), the difference between the potential energies of configuration (2) and (1) is given by: