If the area of the larger portion bounded between the curves \(x^2 + y^2 = 25\) and \(y = |x - 1|\) is \( \frac{1}{4} (b\pi + c) \), where \(b, c \in \mathbb{N}\), then \( b + c \) is equal .
The general solution of the differential equation \[ (x + y)y \,dx + (y - x)x \,dy = 0 \] is:
Find the area of the region (in square units) enclosed by the curves: \[ y^2 = 8(x+2), \quad y^2 = 4(1-x) \] and the Y-axis.