Question

If each diode has a forward bias resistance of 25Ω in the below circuit, Which of the following options is correct:

• A. \(\frac{I_1}{I_2}=1\)
• B. \(\frac{I_2}{I_3}=1\)
• C. \(\frac{I_3}{I_4}=1\)
• D. \(\frac{I_1}{I_2}=2\)

Answer 1

The Correct Option is D

Analyzing the circuit.
From the given circuit, we see that Diodes \( D_1 \) and \( D_3 \) are conducting, while \( D_2 \) is reverse biased. Hence, current \( I_1 \) will be split between \( I_3 \) and \( I_4 \), and \( I_2 = 0 \). Using Kirchhoff's Current Law (KCL), we have: \[ I_1 = I_2 + I_4 + I_3 = 2I_2 \] Thus, the ratio \( \frac{I_1}{I_2} \) is: \[ \frac{I_1}{I_2} = 2 \]