Question:
If each diode has a forward bias resistance of 25Ω in the below circuit, Which of the following options is correct:
If each diode has a forward bias resistance of 25Ω in the below circuit, Which of the following options is correct:
Updated On: Mar 21, 2025
- \(\frac{I_1}{I_2}=1\)
- \(\frac{I_2}{I_3}=1\)
- \(\frac{I_3}{I_4}=1\)
- \(\frac{I_1}{I_2}=2\)
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The Correct Option is D
Solution and Explanation
Analyzing the circuit.
From the given circuit, we see that Diodes \( D_1 \) and \( D_3 \) are conducting, while \( D_2 \) is reverse biased. Hence, current \( I_1 \) will be split between \( I_3 \) and \( I_4 \), and \( I_2 = 0 \). Using Kirchhoff's Current Law (KCL), we have: \[ I_1 = I_2 + I_4 + I_3 = 2I_2 \] Thus, the ratio \( \frac{I_1}{I_2} \) is: \[ \frac{I_1}{I_2} = 2 \]
From the given circuit, we see that Diodes \( D_1 \) and \( D_3 \) are conducting, while \( D_2 \) is reverse biased. Hence, current \( I_1 \) will be split between \( I_3 \) and \( I_4 \), and \( I_2 = 0 \). Using Kirchhoff's Current Law (KCL), we have: \[ I_1 = I_2 + I_4 + I_3 = 2I_2 \] Thus, the ratio \( \frac{I_1}{I_2} \) is: \[ \frac{I_1}{I_2} = 2 \]
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