Using Ohm’s law, which states:
\[
V = IR
\]
Where:
- \( I = 2 \, \text{A} \) is the current,
- \( R = 5 \, \Omega \) is the resistance.
Now, substitute the values:
\[
V = 2 \times 5 = 10 \, \text{V}
\]
Thus, the potential difference across the conductor is \( 10 \, \text{V} \).