If $\Delta Q$ is the heat supplied and $\Delta W$ is the work done by the gas at constant pressure, then the ratio $\dfrac{\Delta Q}{\Delta W}$ is ($\gamma$ = specific heat ratio)
Show Hint
- $\gamma$
- $\gamma - 1$
- $\dfrac{\gamma}{1 + \gamma}$
- $\dfrac{\gamma}{\gamma - 1}$
The Correct Option is D
Solution and Explanation
Also, $C_p = \dfrac{\gamma R}{\gamma - 1}$ ⇒ $\Delta Q = n \cdot \dfrac{\gamma R}{\gamma - 1} \cdot \Delta T$
So, $\dfrac{\Delta Q}{\Delta W} = \dfrac{n \cdot \dfrac{\gamma R}{\gamma - 1} \cdot \Delta T}{nR \cdot \Delta T} = \dfrac{\gamma}{\gamma - 1}$
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