If
\(cot α=1\) and \(sec β=−\frac{5}{3}\) where \(π<α<\frac{3π}{2} and \frac{π}{2}<β<π\)
, then the value of tan(α + β) and the quadrant in which α + β lies, respectively are :
The correct answer is (A) : \(-\frac{1}{7}\) and IVth quadrant
∵ cot α = 1,
\(α∈(π, \frac{3π}{2})\)
then tan α = 1 and \(sec β=−\frac{5}{3}, β∈(\frac{π}{2},π) \)
then \(tan β=−\frac{4}{3}\)
\(∴tan(α+β)=\frac{tanα+tanβ}{1−tanα⋅tanβ}\)
\(=\frac{1−\frac{4}{3}}{1+\frac{4}{3}}\)
\(=−\frac{1}{7}\)
\(α+β∈(\frac{3π}{2},2π)\)
i.e. fourth quadrant
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