If 
For a \( 2 \times 2 \) matrix, the determinant is calculated as \( ad - bc \) for a matrix
Step 1: Analyzing the given matrix equation.
The matrix equation is: 
Step 2: Using the determinant of the matrix.
The determinant of a \( 2 \times 2 \) matrix is given by: \[ \text{det}(A) = (x - 2y)(x) - (0)(5) \] This simplifies to: \[ \text{det}(A) = x(x - 2y) \] Step 3: Solving for \( y \).
We are given that the determinant is equal to 0, so: \[ x(x - 2y) = 0 \] This implies that either \( x = 0 \) or \( x - 2y = 0 \).
Step 4: Conclusion.
From \( x - 2y = 0 \), we get \( y = \frac{x}{2} \). Substituting the values, we find that \( y = 2 \), corresponding to option (C).
Let \[ f(x)=\int \frac{7x^{10}+9x^8}{(1+x^2+2x^9)^2}\,dx \] and $f(1)=\frac14$. Given that 
and $B=\operatorname{adj}(\operatorname{adj}A)$, if $|B|=81$, find the value of $\alpha^2$ (where $\alpha\in\mathbb{R}$).
Let \[ f(x)=\int \frac{7x^{10}+9x^8}{(1+x^2+2x^9)^2}\,dx \] and $f(1)=\frac14$. Given that 