Question:

If \( ax + by = 1 \) is a normal to the parabola \( y^2 = 4px \), then the condition is

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To find conditions for normals to a parabola, use parametric coordinates and compare forms.
Updated On: May 18, 2025
  • \( 4ab = a^2 + b^2 \)
  • \( 4pab + ab^3 = a^2b^2 \)
  • \( pa^3 = b^2 - 2pab^2 \)
  • \( pa^2 + 4pa = a + b \)
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The Correct Option is C

Solution and Explanation

The general equation of a normal to the parabola \( y^2 = 4px \) at point \( (pt^2, 2pt) \) is given by:
\( y = -tx + 2pt + pt^3 \). Rewriting in the form \( ax + by = 1 \), we compare it with the given line.
Through derivation and elimination, the condition becomes:
\[ pa^3 = b^2 - 2pab^2 \]
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