Question:

If $\sin\,\theta$ and $\cos \theta $ are the roots of the equation $ax^2 - bx + c = 0$, then $a, b$ and $c$ satisfy the relation

Updated On: Apr 27, 2024
  • $a^2 + b^2 + 2ac = 0$
  • $a^2 - b^2 + 2ac = 0$
  • $a^2 + c^2 + 2ab = 0$
  • $a^2 - b^2 - 2ac = 0$
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The Correct Option is B

Solution and Explanation

Since, $\sin \theta$ and $\cos \theta$ are the roots of the equation $a x^{2}-b x+c=0$
$\therefore \sin \theta+\cos \theta=\frac{b}{a}$ and $\sin \theta \cos \theta=\frac{c}{a}$
$\Rightarrow \left(\sin ^{2} \theta+\cos ^{2} \theta+2 \sin \theta \cos \theta\right)=\frac{b^{2}}{a^{2}}$
$\Rightarrow 1+2 \sin \theta \cos \theta=\frac{b^{2}}{a^{2}}$
$\Rightarrow 1+2 \times \frac{c}{a}=\frac{b^{2}}{a^{2}}$
$\Rightarrow a^{2}-b^{2}+2 a c=0$
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Concepts Used:

Complex Numbers and Quadratic Equations

Complex Number: Any number that is formed as a+ib is called a complex number. For example: 9+3i,7+8i are complex numbers. Here i = -1. With this we can say that i² = 1. So, for every equation which does not have a real solution we can use i = -1.

Quadratic equation: A polynomial that has two roots or is of the degree 2 is called a quadratic equation. The general form of a quadratic equation is y=ax²+bx+c. Here a≠0, b and c are the real numbers.