Concept: For a quadratic equation \(ax^2+bx+c=0\), if \(\alpha\) and \(\beta\) are its roots, then:
Sum of roots: \(\alpha + \beta = -b/a\)
Product of roots: \(\alpha\beta = c/a\)
We need to simplify the given expression in terms of \(\alpha+\beta\) and \(\alpha\beta\).
Step 1: Find the sum and product of the roots for the given equation
The equation is \( 2x^2 - 4x + 1 = 0 \).
Here, \(a=2\), \(b=-4\), \(c=1\).
Sum of roots: \(\alpha + \beta = -(-4)/2 = 4/2 = 2\).
Product of roots: \(\alpha\beta = 1/2\).
Step 2: Simplify the expression to be evaluated
The expression is \( \frac{1}{\alpha^2\beta} + \frac{1}{\alpha\beta^2} \).
To add these fractions, find a common denominator. The common denominator is \(\alpha^2\beta^2\).
\[ \frac{1}{\alpha^2\beta} + \frac{1}{\alpha\beta^2} = \frac{\beta}{\alpha^2\beta^2} + \frac{\alpha}{\alpha^2\beta^2} \]
\[ = \frac{\beta + \alpha}{\alpha^2\beta^2} \]
This can be written as:
\[ = \frac{\alpha + \beta}{(\alpha\beta)^2} \]
Step 3: Substitute the values of \(\alpha+\beta\) and \(\alpha\beta\)
We found:
\(\alpha + \beta = 2\)
\(\alpha\beta = 1/2\)
Substitute these into the simplified expression:
\[ \frac{2}{\left(\frac{1}{2}\right)^2} \]
First, calculate \((\frac{1}{2})^2\):
\[ \left(\frac{1}{2}\right)^2 = \frac{1^2}{2^2} = \frac{1}{4} \]
Now the expression becomes:
\[ \frac{2}{\frac{1}{4}} \]
To divide by a fraction, multiply by its reciprocal:
\[ 2 \times \frac{4}{1} = 2 \times 4 = 8 \]
The value of the expression is 8.