If ABCD is a parallelogram, vector AB = 2i + 4j - 5k and vector AD = i + 2j + 3k, then the unit vector in the direction of BD is
If ABCD is a parallelogram, vector AB = 2i + 4j - 5k and vector AD = i + 2j + 3k, then the unit vector in the direction of BD is
\(\frac{1}{√69}(\hat{i}+2\hat{j}-8\hat{k})\)
\(\frac{1}{69}(\hat{i}+2\hat{j}-8\hat{k})\)
\(\frac{1}{√69}(\hat{-i}-2\hat{j}+8\hat{k})\)
\(\frac{1}{69}(\hat{-i}-2\hat{j}+8\hat{k})\)
The Correct Option is C
Solution and Explanation
The correct answer is option C) \(\frac{1}{√69}(\hat{-i}-2\hat{j}+8\hat{k})\)
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