If a radioactive element with a half-life of 30 min undergoes beta decay. The fraction of the radioactive element that remains undecayed after 90 min is:
For radioactive decay:
1. Number of Half-Lives: - Time elapsed: t = 90 min. - Half-life: T1/2 = 30 min. - Number of half-lives:
\[n = \frac{t}{T_{1/2}} = \frac{90}{30} = 3.\]
2. Remaining Fraction: - Fraction remaining after n half-lives:
\[\frac{N}{N_0} = \left(\frac{1}{2}\right)^n = \left(\frac{1}{2}\right)^3 = \frac{1}{8}.\]
Final Answer:
\(\boxed{\frac{1}{8}}\)

In the first configuration (1) as shown in the figure, four identical charges \( q_0 \) are kept at the corners A, B, C and D of square of side length \( a \). In the second configuration (2), the same charges are shifted to mid points C, E, H, and F of the square. If \( K = \frac{1}{4\pi \epsilon_0} \), the difference between the potential energies of configuration (2) and (1) is given by: