If a copper wire is stretched to increase its length by \(20 \%\) The percentage increase in resistance of the wire is _______\(\%\).
When a wire is stretched, the resistance increases as R ∝ L2 (if volume remains constant).
Solution:
The resistance of a wire is given by:
\[ R = \rho \frac{L}{A} \]
where \(L\) is the length and \(A\) is the cross-sectional area. When a wire is stretched, its volume remains constant:
\[ L_1 A_1 = L_2 A_2 \]
As \(L_2 = 1.2L_1\), the area decreases as:
\[ A_2 = \frac{A_1}{1.2} \]
The new resistance is:
\[ R_2 = \rho \frac{L_2}{A_2} = \rho \frac{1.2L_1}{A_1 / 1.2} = 1.44R_1 \]
The percentage increase in resistance is:
\[ \% \, \text{Increase} = \frac{R_2 - R_1}{R_1} \times 100 = \frac{1.44R_1 - R_1}{R_1} \times 100 = 44\% \]
Thus, the resistance increases by 44%.
The correct answer is 44.
As volume is constant,
So resistance ∝ (length )2
⇒% change in resistance
\(\frac{1.44 R_0}{R_0}×100=0.44×100\)
\(=44\%\)
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is:
Current electricity is defined as the flow of electrons from one section of the circuit to another.
There are two types of current electricity as follows:
The current electricity whose direction remains the same is known as direct current. Direct current is defined by the constant flow of electrons from a region of high electron density to a region of low electron density. DC is used in many household appliances and applications that involve a battery.
The current electricity that is bidirectional and keeps changing the direction of the charge flow is known as alternating current. The bi-directionality is caused by a sinusoidally varying current and voltage that reverses directions, creating a periodic back-and-forth motion for the current. The electrical outlets at our homes and industries are supplied with alternating current.