Step 1: Recall determinant formula
\[ \det(A) = ad - bc \] For \[ A = \begin{pmatrix} 2 & 3 \\ 1 & k \end{pmatrix}, \] we have \(a=2\), \(b=3\), \(c=1\), and \(d=k\).
Step 2: Write determinant equation
\[ \det(A) = 2 \times k - 3 \times 1 = 2k - 3 \]
Step 3: Use given determinant value
\[ 2k - 3 = 7 \implies 2k = 10 \implies k = 5 \]
If $ A = \left[\begin{array}{cc} 3 & 1 \\2 & 4 \end{array}\right] $, then the determinant of the adjoint of $ A^2 $ is:
If \[ A = \begin{bmatrix} 1 & 2 & 0 \\ -2 & -1 & -2 \\ 0 & -1 & 1 \end{bmatrix} \] then find \( A^{-1} \). Hence, solve the system of linear equations: \[ x - 2y = 10, \] \[ 2x - y - z = 8, \] \[ -2y + z = 7. \]
The scientist's theory was initially met with _________, but later gained widespread acclaim after consistent experimental validation.