Question:

For a matrix $ A $ of order $ 3 \times 3 $, which of the following is true?

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The adjugate of a matrix \( A \) is related to its inverse when the determinant of \( A \) is non-zero. Specifically, \( A^{-1} = \frac{1}{|A|} \cdot \text{adj}(A) \).
Updated On: May 14, 2025
  • \( \text{adj}(A) = A^2 \)
  • \( \text{adj}(A) \neq A^2 \)
  • \( \text{adj}(A) = A^T \)
  • \( \text{adj}(A) = A^{-1} \) 

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The Correct Option is D

Solution and Explanation

For any square matrix \( A \), the adjugate (or adjoint) of the matrix \( A \), denoted \( \text{adj}(A) \), has the following property: \[ A \cdot \text{adj}(A) = |A| \cdot I \] Where:
- \( A \) is the matrix
- \( \text{adj}(A) \) is the adjugate matrix of \( A \)
- \( |A| \) is the determinant of \( A \)
- \( I \) is the identity matrix of the same order as \( A \)
For a matrix \( A \) of order \( 3 \times 3 \), when the determinant of \( A \) is non-zero, we can express the inverse of \( A \) as: \[ A^{-1} = \frac{1}{|A|} \cdot \text{adj}(A) \] Therefore, for a matrix \( A \), the adjugate of \( A \) is related to the inverse of \( A \) by the equation: \[ \text{adj}(A) = A^{-1} \] Thus, the correct answer is \( \text{adj}(A) = A^{-1} \).
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