Step 1: The quadratic equation is:
\[ ax^2 + bx + c = 0 \]
where \( a, b, c \) are distinct odd natural numbers.
Step 2: The discriminant \( \Delta \) of the quadratic equation is:
\[ \Delta = b^2 - 4ac \]
For the quadratic to have rational roots, the discriminant must be a perfect square.
Step 3: Since \( a, b, c \) are distinct odd natural numbers, \( b^2 \) is odd, and \( 4ac \) is also odd (since \( a \) and \( c \) are odd). Thus, \( b^2 - 4ac \) is even.
Step 4: However, the difference of an odd number and an even number is always odd, so the discriminant cannot be a perfect square.
Step 5: Therefore, the equation has no rational roots.
Match List I with List II :
| List I (Quadratic equations) | List II (Roots) |
|---|---|
| (A) \(12x^2 - 7x + 1 = 0\) | (I) \((-13, -4)\) |
| (B) \(20x^2 - 9x + 1 = 0\) | (II) \(\left(\frac{1}{3}, \frac{1}{4}\right)\) |
| (C) \(x^2 + 17x + 52 = 0\) | (III) \((-4, -\frac{3}{2})\) |
| (D) \(2x^2 + 11x + 12 = 0\) | (IV) \(\left(\frac{1}{5}, \frac{1}{4}\right)\) |
Choose the correct answer from the options given below :

Which of the following statement(s) is/are correct about the given compound?
