Question

If 5.6 liters of a monoatomic gas at STP is adiabatically compressed to 0.7 liters, then the work done on the gas is nearly

• A. 307R
• B. 357R
• C. 367R
• D. 407R

Hint:

For adiabatic processes, remember that \( P V^\gamma = \text{constant} \), and use this to solve for the work done in such transformations.

Answer 1

The Correct Option is A

The work done during an adiabatic process can be calculated using the formula \( W = \frac{P_1 V_1 \gamma}{\gamma - 1} \), where \( \gamma \) is the adiabatic index, and \( P_1, V_1 \) are the initial pressure and volume. By substituting the known values, we get 307R as the work done.