Question:
If \( 4x - 3y - 5 = 0 \) is a normal to the ellipse \( 3x^2 + 8y^2 = k \), then the equation of the tangent at point (-2,m) is:
If \( 4x - 3y - 5 = 0 \) is a normal to the ellipse \( 3x^2 + 8y^2 = k \), then the equation of the tangent at point (-2,m) is:
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For ellipse normal and tangent problems, use implicit differentiation or standard normal-tangent relations.
Updated On: Apr 18, 2025
- \( 3x + 4y - 14 = 0 \)
- \( 3x - 4y + 10 = 0 \)
- \( 3x - 4y + 1 = 0 \)
- \( 4x + 3y - 3 = 0 \)
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The Correct Option is B
Solution and Explanation
Step 1: Using the normal equation condition
A normal to an ellipse satisfies the equation:
\[
ax + by + c = 0
\]
We substitute \( x = -2 \), solve for \( y \), and derive the tangent equation.
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