Question:

If 1.01.0 mole of I2I_{2} is introduced into 1.01.0 litre flask at 1000K1000\, K, at equilibrium (Kc=106)\left(K_{c}=10^{-6}\right), which one is correct?

Updated On: Jan 30, 2025
  • [I2(g)]>[I(g)]\left[ I _{2}( g )\right]>\left[ I ^{-}( g )\right]
  • $\left[ I _{2}( g )\right]
  • [I2(g)]=[I(g)]\left[ I _{2}( g )\right]=\left[ I ^{-}( g )\right]
  • [I2(g)]=12[I(g)]\left[ I _{2}( g )\right]=\frac{1}{2}\left[ I ^{-}( g )\right]
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The Correct Option is B

Solution and Explanation

${ $\underset{\text{ 1 -x}}{{I_{2} }}$
<=> 2I 2x \underset{\text{ 2x }}{{ 2 I^{-} }}
}$
Kc=(2x)2(1x)=106K_c = \frac{(2x)^2}{(1-x)} = 10^{-6}
It shows that (1 - x) < 2x
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