The given equation is a first-order linear differential equation. To find the integrating factor, we use the formula for the integrating factor for a linear equation of the form \( \frac{dy}{dx} + P(x)y = Q(x) \), which is:
\[
\mu(x) = e^{\int P(x) \, dx}
\]
For the equation \( \frac{dy}{dx} - 2y = 2x - 3 \), \( P(x) = -2 \). Therefore, the integrating factor is:
\[
\mu(x) = e^{\int -2 \, dx} = e^{-2x}
\]
Thus, the integrating factor is \( e^{-2x} \).