![Identify the products [A] and [B] respectively in the following reaction:](https://images.collegedunia.com/public/qa/images/content/2025_03_17/Screenshot_677f6f511742225539486.png)




To determine the products [A] and [B] in the given reaction, let's analyze each step:
The initial reactant is chlorobenzene (C6H5Cl). The reaction with \(\text{NaOH}\hspace{2pt} \text{at} \hspace{2pt} 623 \hspace{2pt} \text{K and} \hspace{2pt} 300 \hspace{2pt} \text{atm}\) is typical of a nucleophilic aromatic substitution. Under these harsh conditions, the chlorine atom is replaced by an OH group, forming phenol (C6H5OH).
Next, phenol (C6H5OH) is oxidized using \(\text{Na}_{2}\text{Cr}_{2}\text{O}_{7} \hspace{2pt} \text{in} \hspace{2pt} \text{H}_{2}\text{SO}_{4}\). This is a classic oxidation reaction where phenol is oxidized to benzoquinone.
So, the products are:
The correct answer matches the provided option with products , which indicates phenol followed by oxidation to benzoquinone.
To identify the products [A] and [B] in the given chemical reaction, let's go through the reaction step-by-step.
The first step of the reaction involves the use of NaOH at high temperature (623K) and pressure (300 atm). This condition is typical for a nucleophilic aromatic substitution reaction known as the Dow process. In this process, chlorobenzene reacts with NaOH to form phenol.
Thus, product [A] is phenol.
In the second step, phenol is oxidized using sodium dichromate (\( \text{Na}_2\text{Cr}_2\text{O}_7 \)) and sulfuric acid (\(\text{H}_2\text{SO}_4\)). This is a common oxidation reaction where phenol is converted to benzoquinone.
Thus, product [B] is benzoquinone.
Let's confirm this by matching the products with the correct option from those provided.
The correct answer is that product [A] is phenol, and product [B] is benzoquinone, matching the given option.
In the given figure, the blocks $A$, $B$ and $C$ weigh $4\,\text{kg}$, $6\,\text{kg}$ and $8\,\text{kg}$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is ___ N.
(Given: $g = 10\,\text{m s}^{-2}$) 
Two circular discs of radius \(10\) cm each are joined at their centres by a rod, as shown in the figure. The length of the rod is \(30\) cm and its mass is \(600\) g. The mass of each disc is also \(600\) g. If the applied torque between the two discs is \(43\times10^{-7}\) dyne·cm, then the angular acceleration of the system about the given axis \(AB\) is ________ rad s\(^{-2}\).
