Consider the following reactions:
\[
K_2Cr_2O_7 + 2 KOH \xrightarrow{ \text{heat} } [A]
\]
\[
[A] + H_2SO_4 \xrightarrow{} [B] + K_2SO_4
\]
The products [A] and [B], respectively are:
Show Hint
- \( K_2Cr(OH)_6 \) and \( Cr_2O_3 \)
- \( K_2CrO_4 \) and \( Cr_2O_3 \)
- \( K_2CrO_4 \) and \( K_2Cr_2O_7 \)
- \( K_2CrO_4 \) and \( CrO \)
The Correct Option is C
Approach Solution - 1
To solve this question, we need to analyze the given chemical reactions step-by-step and determine the products [A] and [B]. Let's go through the reactions:
- The first reaction is:
\(K_2Cr_2O_7 + 2 KOH \xrightarrow{ \text{heat} } [A]\)
In this reaction, potassium dichromate \(K_2Cr_2O_7\) reacts with potassium hydroxide \(KOH\) under heat. The product formed, [A], is potassium chromate \(K_2CrO_4\). This involves a change from the dichromate anion to the chromate anion.
- The second reaction is:
\([A] + H_2SO_4 \xrightarrow{} [B] + K_2SO_4\)
In this reaction, [A] (which we identified as \(K_2CrO_4\)) reacts with sulfuric acid \(H_2SO_4\). This reaction converts the chromate ion back to the dichromate ion. The product [B] is potassium dichromate, \(K_2Cr_2O_7\), and potassium sulfate \(K_2SO_4\) is also formed.
Therefore, the correct products for the reactions are:
- [A]: \(K_2CrO_4\)
- [B]: \(K_2Cr_2O_7\)
Given these deductions, the correctly matched products according to the options provided are:
\(K_2CrO_4\) and \(K_2Cr_2O_7\)
Approach Solution -2
- In the second reaction, \( K_2CrO_4 \) reacts with sulfuric acid (H2SO4), resulting in chromium trioxide \( Cr_2O_3 \) as the product [B]. Thus, the correct products are [A] = \( K_2CrO_4 \) and [B] = \( K_2Cr_2O_7 \).
Top Questions on Reactions of Chromium Compounds
- Identify the products [A] and [B] respectively in the following reaction:
![Identify the products [A] and [B] respectively in the following reaction:](https://images.collegedunia.com/public/qa/images/content/2025_03_17/Screenshot_677f6f511742225539486.png)
- JEE Main - 2025
- Chemistry
- Reactions of Chromium Compounds
Questions Asked in JEE Main exam
Given below are two statements:
Statement (I):
are isomeric compounds.
Statement (II):
are functional group isomers.
In the light of the above statements, choose the correct answer from the options given below:- JEE Main - 2025
- Isomerism
- Let ABC be a triangle formed by the lines \( 7x - 6y + 3 = 0 \), \( x + 2y - 31 = 0 \), and \( 9x - 2y - 19 = 0 \). Let the point \( (h, k) \) be the image of the centroid of \( \triangle ABC \) in the line \( 3x + 6y - 53 = 0 \). Then \( h^2 + k^2 + hk \) is equal to:
- JEE Main - 2025
- Coordinate Geometry
- For a reaction, $$ {N}_2{O}_5(g) \rightarrow 2{NO}_2(g) + \frac{1}{2} {O}_2(g) $$ in a constant volume container, no products were present initially. The final pressure of the system when 50% of the reaction gets completed is:
- JEE Main - 2025
- Chemical Reactions
- If the image of the point $ P(1, 0, 3) $ in the line joining the points $ A(4, 7, 1) $ and $ B(3, 5, 3) $ is $ Q(\alpha, \beta, \gamma) $, then $ \alpha + \beta + \gamma $ is equal to:
- JEE Main - 2025
- 3D Geometry
Among the following cations, the number of cations which will give characteristic precipitate in their identification tests with
\(K_4\)[Fe(CN)\(_6\)] is : \[ {Cu}^{2+}, \, {Fe}^{3+}, \, {Ba}^{2+}, \, {Ca}^{2+}, \, {NH}_4^+, \, {Mg}^{2+}, \, {Zn}^{2+} \]- JEE Main - 2025
- Qualitative Analysis