The reaction involves Zn-Hg and HCl, which is known as the Clemmensen reduction. Clemmensen reduction is typically used to reduce carbonyl groups (like aldehydes and ketones) to methylene (-CH2-) groups.
The starting compound likely has a carbonyl (C=O) group. In the presence of Zn-Hg and HCl, the carbonyl group will be reduced to a -CH2- group.
Based on the Clemmensen reduction, the product will have the carbonyl group replaced by a methylene (-CH2-) group. Among the given options, Option (4) represents the structure where the carbonyl group has been reduced to a -CH2- group.
The correct product of the reaction is represented by Option (4).
Let one focus of the hyperbola $ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 $ be at $ (\sqrt{10}, 0) $, and the corresponding directrix be $ x = \frac{\sqrt{10}}{2} $. If $ e $ and $ l $ are the eccentricity and the latus rectum respectively, then $ 9(e^2 + l) $ is equal to:
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is: