The reaction involves Zn-Hg and HCl, which is known as the Clemmensen reduction. Clemmensen reduction is typically used to reduce carbonyl groups (like aldehydes and ketones) to methylene (-CH2-) groups.
The starting compound likely has a carbonyl (C=O) group. In the presence of Zn-Hg and HCl, the carbonyl group will be reduced to a -CH2- group.
Based on the Clemmensen reduction, the product will have the carbonyl group replaced by a methylene (-CH2-) group. Among the given options, Option (4) represents the structure where the carbonyl group has been reduced to a -CH2- group.
The correct product of the reaction is represented by Option (4).
In the following circuit, the reading of the ammeter will be: (Take Zener breakdown voltage = 4 V)
If $10 \sin^4 \theta + 15 \cos^4 \theta = 6$, then the value of $\frac{27 \csc^6 \theta + 8 \sec^6 \theta}{16 \sec^8 \theta}$ is:
If the area of the region $\{ (x, y) : |x - 5| \leq y \leq 4\sqrt{x} \}$ is $A$, then $3A$ is equal to
Let $A = \begin{bmatrix} \cos \theta & 0 & -\sin \theta \\ 0 & 1 & 0 \\ \sin \theta & 0 & \cos \theta \end{bmatrix}$. If for some $\theta \in (0, \pi)$, $A^2 = A^T$, then the sum of the diagonal elements of the matrix $(A + I)^3 + (A - I)^3 - 6A$ is equal to
Let $A = \{ z \in \mathbb{C} : |z - 2 - i| = 3 \}$, $B = \{ z \in \mathbb{C} : \text{Re}(z - iz) = 2 \}$, and $S = A \cap B$. Then $\sum_{z \in S} |z|^2$ is equal to