Step 1: Analyze each statement.
- (A) \( -\text{OCH}_3 \) and \( -\text{NHCOCH}_3 \) are activating groups.
This statement is correct. Both \( -\text{OCH}_3 \) (methoxy group) and \( -\text{NHCOCH}_3 \) (acetamido group) are electron-donating groups. These groups increase the electron density on the aromatic ring and activate the ring toward electrophilic substitution reactions. Therefore, they are activating groups.
- (B) \( -\text{CN} \) and \( -\text{OH} \) are meta directing groups.
This statement is correct. \( -\text{CN} \) (cyano group) and \( -\text{OH} \) (hydroxyl group) are electron-withdrawing groups, and they direct substituents to the meta position on the aromatic ring in electrophilic substitution reactions.
- (C) \( -\text{CN} \) and \( -\text{SO}_3\text{H} \) are meta directing groups.
This statement is correct. Both \( -\text{CN} \) (cyano group) and \( -\text{SO}_3\text{H} \) (sulfonic acid group) are electron-withdrawing groups and they direct substituents to the meta position during electrophilic substitution reactions.
- (D) Activating groups act as ortho- and para-directing groups.
This statement is correct. Activating groups, such as \( -\text{OH} \), \( -\text{OCH}_3 \), and others, increase the electron density on the aromatic ring and direct new substituents to the ortho and para positions in electrophilic substitution reactions.
- (E) Halides are activating groups.
This statement is incorrect. Halides (e.g., \( -\text{Cl} \), \( -\text{Br} \)) are deactivating groups due to their electron-withdrawing nature through induction. However, halides are ortho- and para-directing groups due to their lone pair donation through resonance.
Step 2: Conclusion.
The correct statements are (A), (B), and (E).
Final Answer:
\[
\boxed{\text{(A), (B) and (E) only}}.
\]