How many molecules are present in 11.2 L of \(CO_{2}\) at STP?
Step 1: At STP (Standard Temperature and Pressure), 1 mole of any ideal gas occupies 22.4 L.
Step 2: Therefore, the number of moles in 11.2 L of \(CO_{2}\)} is: \[ \text{Moles} = \frac{11.2}{22.4} = 0.5 \text{ mol} \] Step 3: 1 mole contains \(6.022 \times 10^{23}\) molecules (Avogadro’s number). So, \[ \text{Number of molecules} = 0.5 \times 6.022 \times 10^{23} = 3.011 \times 10^{23} \]
0.1 mole of compound S will weigh ...... g, (given the molar mass in g mol\(^{-1}\) C = 12, H = 1, O = 16) 