0.1 mole of compound S will weigh ...... g, (given the molar mass in g mol\(^{-1}\) C = 12, H = 1, O = 16)
To determine the weight in grams of 0.1 mole of compound S, we first need to calculate the molar mass of compound S using its chemical formula. The compound S given is C2H6O.
Calculate the molar mass of C2H6O:
Adding these values together gives the molar mass of C2H6O:
Molar Mass = 24 + 6 + 16 = 46 g/mol
To find the weight of 0.1 mole of C2H6O, use the formula:
Weight = Moles × Molar Mass
Weight of 0.1 mole = 0.1 × 46 = 4.6 g
The calculated weight is 4.6 g, which precisely matches the expected range of 4.6,4.6, confirming the correctness of the solution.
The molar mass of the water insoluble product formed from the fusion of chromite ore \(FeCr_2\text{O}_4\) with \(Na_2\text{CO}_3\) in presence of \(O_2\) is ....... g mol\(^{-1}\):
0.1 mol of the following given antiviral compound (P) will weigh .........x $ 10^{-1} $ g.
Let \( S = \left\{ m \in \mathbb{Z} : A^m + A^m = 3I - A^{-6} \right\} \), where
\[ A = \begin{bmatrix} 2 & -1 \\ 1 & 0 \end{bmatrix} \]Then \( n(S) \) is equal to ______.
Two vessels A and B are connected via stopcock. Vessel A is filled with a gas at a certain pressure. The entire assembly is immersed in water and allowed to come to thermal equilibrium with water. After opening the stopcock the gas from vessel A expands into vessel B and no change in temperature is observed in the thermometer. Which of the following statement is true?
Choose the correct nuclear process from the below options:
\( [ p : \text{proton}, n : \text{neutron}, e^- : \text{electron}, e^+ : \text{positron}, \nu : \text{neutrino}, \bar{\nu} : \text{antineutrino} ] \)
Let \( T_r \) be the \( r^{\text{th}} \) term of an A.P. If for some \( m \), \( T_m = \dfrac{1}{25} \), \( T_{25} = \dfrac{1}{20} \), and \( \displaystyle\sum_{r=1}^{25} T_r = 13 \), then \( 5m \displaystyle\sum_{r=m}^{2m} T_r \) is equal to: