How many compounds have a linear shape among \( \text{SO}_2 \), \( \text{BeCl}_2 \), \( \text{N}_3^- \), \( \text{I}_3^- \), \( \text{NO}_2^+ \), \( \text{NO}_2 \)?
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To determine the shape of a molecule, consider the number of bonding pairs and lone pairs around the central atom using the VSEPR theory.
The compounds that have a linear shape are:
- \( \text{BeCl}_2 \) (linear)
- \( \text{N}_3^- \) (linear)
- \( \text{I}_3^- \) (linear)
Therefore, there are 3 compounds with a linear shape.