\(H_2O_2\) behave like reducing agent in which of the following reactions:
\(Fe^{+2}+ H_2O_2 → Fe^{+3} + H_2O\)
\(H_2S+H_2O_2 → SO^{2-}_4+H_2O\)
\(HOCl + H_2O_2 → Cl^- + 2H_2O + O_2\)
\(Mn^{+2} + H_2O_2 → MnO_2 + H_2O\)
\(H_2O_2\) reduces \(HOCl\) to \(Cl^-\) and itself gets oxidised to \(O_2.\)
The correct option is (c ): \(HOCl + H_2O_2 → Cl^- + 2H_2O + O_2\)
A square loop of sides \( a = 1 \, {m} \) is held normally in front of a point charge \( q = 1 \, {C} \). The flux of the electric field through the shaded region is \( \frac{5}{p} \times \frac{1}{\varepsilon_0} \, {Nm}^2/{C} \), where the value of \( p \) is: