When white light passes through a prism, it undergoes dispersion due to varying refractive indices for different wavelengths. Among the colors in the visible spectrum, red light has the longest wavelength, while violet has the shortest. Since the refractive index is inversely proportional to the wavelength, red light bends the least, while violet light bends the most.
This phenomenon occurs because a higher refractive index results in greater bending, and shorter wavelengths correspond to higher refractive indices. Thus, red light deviates less compared to yellow and violet.
As \( \lambda_{\text{red}} > \lambda_{\text{yellow}} > \lambda_{\text{violet}} \), light rays with longer wavelengths bend less.
Therefore, both Statement I and Statement II are true.
Match List-I with List-II for the index of refraction for yellow light of sodium (589 nm)
LIST-I (Materials) | LIST-II (Refractive Indices) | ||
---|---|---|---|
A. | Ice | I. | 1.309 |
B. | Rock salt (NaCl) | II. | 1.460 |
C. | CCl₄ | III. | 1.544 |
D. | Diamond | IV. | 2.417 |
Choose the correct answer from the options given below:
Match the LIST-I with LIST-II
LIST-I | LIST-II | ||
---|---|---|---|
A. | Compton Effect | IV. | Scattering |
B. | Colors in thin film | II. | Interference |
C. | Double Refraction | III. | Polarization |
D. | Bragg's Equation | I. | Diffraction |
Choose the correct answer from the options given below:
A bead of mass \( m \) slides without friction on the wall of a vertical circular hoop of radius \( R \) as shown in figure. The bead moves under the combined action of gravity and a massless spring \( k \) attached to the bottom of the hoop. The equilibrium length of the spring is \( R \). If the bead is released from the top of the hoop with (negligible) zero initial speed, the velocity of the bead, when the length of spring becomes \( R \), would be (spring constant is \( k \), \( g \) is acceleration due to gravity):
Let $ f: \mathbb{R} \to \mathbb{R} $ be a twice differentiable function such that $$ f''(x)\sin\left(\frac{x}{2}\right) + f'(2x - 2y) = (\cos x)\sin(y + 2x) + f(2x - 2y) $$ for all $ x, y \in \mathbb{R} $. If $ f(0) = 1 $, then the value of $ 24f^{(4)}\left(\frac{5\pi}{3}\right) $ is: