The \(π-bond\) present is alkenes is weaker than \(σ-bond\) present in alkanes.
That makes alkenes less stable than alkanes.
Hence, statement-I is correct.
Carbon-carbon double bond is stronger than Carbon-carbon single bond because more energy is required to break 1 sigma and 1 pi bond than to break 1 sigma bond only.
Hence, statement-II is also correct.
Therefore, the correct option is (A): Both Statement I and Statement II are correct.
The molality of a 10% (v/v) solution of di-bromine solution in \(\text{CCl}_4\) (carbon tetrachloride) is \(x\). \(x = \, \_\_\_\_\ \times 10^{-2} \, \text{M}\). (Nearest integer)
Given:
Molar mass of \(\text{Br}_2 = 160 \, \text{g mol}^{-1}\)
Atomic mass of \(\text{C} = 12 \, \text{g mol}^{-1}\)
Atomic mass of \(\text{Cl} = 35.5 \, \text{g mol}^{-1}\)
Density of dibromine = \(3.2 \, \text{g cm}^{-3}\)
Density of \(\text{CCl}_4 = 1.6 \, \text{g cm}^{-3}\)
An alkene X on ozonolysis gives a mixture of Propan-2-one and methanal. What is X?
List-I | List-II | ||
(A) | Cyanocobalamine | (I) | Hydrogenation of Alkenes |
(B) | Wilkinson catalyst | (II) | Antipernicious anemia factor |
(C) | D-penicillamine | (III) | Refining of Ni |
(D) | Mond's Process | (IV) | Treatment of toxic effects of copper |
In organic chemistry, an alkene is a hydrocarbon containing a carbon-carbon double bond.[1]
Alkene is often used as synonym of olefin, that is, any hydrocarbon containing one or more double bonds.
Read More: Ozonolysis
Read More: Unsaturated Hydrocarbon