Given below are two statements:
Statement I: The boiling point of hydrides of Group 16 elements follow the order H2O > H2Te > H2Se > H2S.
Statement II: On the basis of molecular mass, H2O is expected to have lower boiling point than the other members of the group but due to the presence of extensive H-bonding in H2O, it has higher boiling point.
In the light of the above statements, choose the correct answer from the options given below:
Explanation:
Statement I:
The boiling points of the hydrides of Group 16 elements generally increase with increasing molecular mass. However, water (H2O) is an exception due to strong hydrogen bonding. The correct order is H2O > H2Te > H2Se > H2S. Therefore, Statement I is correct.
Statement II:
As stated, based on molecular mass alone, H2O should have the lowest boiling point. However, the extensive intermolecular hydrogen bonding in water significantly increases its boiling point, making it higher than the other hydrides in the group. Thus, Statement II is also correct.
Conclusion:
Both Statement I and Statement II are True.
A bob of heavy mass \(m\) is suspended by a light string of length \(l\). The bob is given a horizontal velocity \(v_0\) as shown in figure. If the string gets slack at some point P making an angle \( \theta \) from the horizontal, the ratio of the speed \(v\) of the bob at point P to its initial speed \(v_0\) is :