Given below are two statements:
Statement I: The boiling point of hydrides of Group 16 elements follow the order H2O > H2Te > H2Se > H2S.
Statement II: On the basis of molecular mass, H2O is expected to have lower boiling point than the other members of the group but due to the presence of extensive H-bonding in H2O, it has higher boiling point.
In the light of the above statements, choose the correct answer from the options given below:
Explanation:
Statement I:
The boiling points of the hydrides of Group 16 elements generally increase with increasing molecular mass. However, water (H2O) is an exception due to strong hydrogen bonding. The correct order is H2O > H2Te > H2Se > H2S. Therefore, Statement I is correct.
Statement II:
As stated, based on molecular mass alone, H2O should have the lowest boiling point. However, the extensive intermolecular hydrogen bonding in water significantly increases its boiling point, making it higher than the other hydrides in the group. Thus, Statement II is also correct.
Conclusion:
Both Statement I and Statement II are True.
Consider a water tank shown in the figure. It has one wall at \(x = L\) and can be taken to be very wide in the z direction. When filled with a liquid of surface tension \(S\) and density \( \rho \), the liquid surface makes angle \( \theta_0 \) (\( \theta_0 < < 1 \)) with the x-axis at \(x = L\). If \(y(x)\) is the height of the surface then the equation for \(y(x)\) is: (take \(g\) as the acceleration due to gravity)
A constant voltage of 50 V is maintained between the points A and B of the circuit shown in the figure. The current through the branch CD of the circuit is :