Why does oxygen show anomalous behavior ?
- Large size, high electronegativity
- Small size, small electronegativity
- Small size, high electronegativity, absence of vacant d- orbital
- Large size high electronegativity presence of vacant d orbital
The Correct Option is C
Solution and Explanation
Top Questions on Group 16 Elements
- Choose the correct statements from the following:
A. All group 16 elements form oxides of general formula \( EO_2 \) and \( EO_3 \) where \( E = S, Se, Te, \) and Po. Both the types of oxides are acidic in nature.
B. TeO\(_2\) is an oxidising agent while SO\(_2\) is reducing in nature.
C. The reducing property decreases from H\(_2\)S to H\(_2\)Te down the group.
D. The ozone molecule contains five lone pairs of electrons.
Choose the correct answer from the options given below:- JEE Main - 2024
- Chemistry
- Group 16 Elements
- From the given list, the number of compounds with +4 oxidation state of Sulphur_____.
\(SO_3, H_2SO_3, SOCl_2, SF_4, BaSO_4, H_2S_2O_7\).- JEE Main - 2024
- Chemistry
- Group 16 Elements
- Given below are two statements :
Statement I: The boiling point of hydrides of Group 16 elements follow the order
H2O > H2Te > H2Se > H2S.
Statement II: On the basis of molecular mass, H2O is expected to have lower boiling point than the other members of the group but due to the presence of extensive H-bonding in H2O, it has higher boiling point.
In the light of the above statements, choose the correct answer from the options given below :- NEET (UG) - 2024
- Chemistry
- Group 16 Elements
- Among Group 16 elements, which one does NOT show -2 oxidation state?
- NEET (UG) - 2024
- Chemistry
- Group 16 Elements
- Cerium (IV) has a noble gas configuration. Which of the following is correct statement about it?
- JEE Main - 2022
- Chemistry
- Group 16 Elements
Questions Asked in JEE Main exam
If $10 \sin^4 \theta + 15 \cos^4 \theta = 6$, then the value of $\frac{27 \csc^6 \theta + 8 \sec^6 \theta}{16 \sec^8 \theta}$ is:
- JEE Main - 2025
- Trigonometric Identities
- If \(\alpha x + \beta y = 109\) is the equation of the chord of the ellipse \[ \frac{x^2}{9} + \frac{y^2}{4} = 1 \] whose midpoint is \(\left(\frac{5}{2}, \frac{1}{2}\right)\), then \(\alpha + \beta\) is equal to:
- JEE Main - 2025
- Coordinate Geometry
A point particle of charge \( Q \) is located at \( P \) along the axis of an electric dipole 1 at a distance \( r \) as shown in the figure. The point \( P \) is also on the equatorial plane of a second electric dipole 2 at a distance \( r \). The dipoles are made of opposite charge \( q \) separated by a distance \( 2a \). For the charge particle at \( P \) not to experience any net force, which of the following correctly describes the situation?
- JEE Main - 2025
- Electrostatics and Work Done by Electric Field
- A rod of linear mass density $ \lambda $ and length $ L $ is bent into the form of a ring of radius $ R $. The moment of inertia of the ring about any of its diameters is:
- JEE Main - 2025
- Moment Of Inertia
- Given below are two statements: Statement (I):
Statement (II):
In the light of the above statements, choose the correct answer from the options given below:- JEE Main - 2025
- Isomerism
Concepts Used:
Group 16 Elements
The group 16 elements (oxygen group elements) of the periodic classification are also known as chalcogens because most of the copper ores have copper in the form of oxides and sulphides. The word chalcogen means “ore formation” which is derived from the Greek word “Chalcos” (Ore) and “gen” (formation).
There are 5 elements that come under Group 16 of the Modern Periodic Table namely:
- Oxygen (O)
- Sulphur (S)
- Selenium (Se)
- Tellurium (Te)
- Polonium (PO)
Electronic Configuration:
The general electronic configuration of the chalcogens can be written as ‘ns2np4’, where ‘n’ denotes the value of the principal quantum number corresponding to the valence shell of the element.
The electron configuration of the synthetic element livermorium (believed to be a chalcogen) is predicted to be [Rn]5f146d107s27p4.
Metallic Nature of the Group 16 Elements:
- Oxygen and sulfur are classified as non-metals.
- Selenium and tellurium are classified as metalloids.
- Under standard conditions, polonium exhibits metallic characteristics. However, it is important to note that polonium is a radioactive element.