Question:
Cerium (IV) has a noble gas configuration. Which of the following is correct statement about it?
Cerium (IV) has a noble gas configuration. Which of the following is correct statement about it?
Updated On: Jul 6, 2024
- It will not prefer to undergo redox reactions.
- It will prefer to gain electron and act as an oxidizing agent
- It will prefer to give away an electron and behave as reducing agent
- It acts as both, oxidizing and reducing agent.
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The Correct Option is B
Solution and Explanation
\(E°\) value of \(Ce^{+4}|Ce^{+3}\) is \(1.74\ V\), which suggests that it is a very good oxidising agent.
So, the correct option is (B): It will prefer to gain electron and act as an oxidizing agent.
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
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- Group 17 Elements: Fluorine family
- Group 18 Elements: Neon family