Draw the possible isomers of:
\[ [ \text{Co}(\text{en})_2\text{Cl}_2 ]^+ \]
Draw the possible isomers of:
\[ [ \text{Co}(\text{en})_2\text{Cl}_2 ]^+ \]
Solution and Explanation
Possible Isomers of the Complex
The complex ion:
\[ [ \text{Co}(\text{en})_2\text{Cl}_2 ]^+ \]
can have two types of geometric isomers: cis and trans.
- Cis isomer: Both Cl− ions are adjacent to each other.
- Trans isomer: The Cl− ions are opposite each other.
Here, “en” stands for ethylenediamine, which is a bidentate ligand. The arrangement of these ligands and the chloride ions around the cobalt center gives rise to these two possible geometric isomers.
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\(X\) is the number of geometrical isomers exhibited by \([\mathrm{Pt(NH_3)(H_2O)BrCl}]\).
\(Y\) is the number of optically inactive isomer(s) exhibited by \([\mathrm{CrCl_2(ox)_2}]^{3-}\).
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The incorrect statements regarding geometrical isomerism are:
(A) Propene shows geometrical isomerism.
(B) Trans isomer has identical atoms/groups on the opposite sides of the double bond.
(C) Cis-but-2-ene has higher dipole moment than trans-but-2-ene.
(D) 2-methylbut-2-ene shows two geometrical isomers.
(E) Trans-isomer has lower melting point than cis isomer.
- Given below are two statements: Statement (I):
Statement (II):
In the light of the above statements, choose the correct answer from the options given below: Given below are two statements:
Statement (I):
are isomeric compounds.
Statement (II):
are functional group isomers.
In the light of the above statements, choose the correct answer from the options given below:
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