Statement I: In Lassaigne's test, the covalent organic molecules are transformed into ionic compounds. This statement is true. Lassaigne's test involves fusing the organic compound with sodium metal. The covalent bonds in the compound break down, forming ionic sodium salts, which are soluble in water and can be easily tested for the presence of elements such as nitrogen (N), sulfur (S), and halogens.
Statement II: The sodium fusion extract of an organic compound having N and S gives prussian blue colour with FeSO4 and Na4[Fe(CN)6]. This statement is false. The correct reaction that leads to the formation of a prussian blue color indicates the presence of nitrogen alone. When both nitrogen and sulfur are present in the sodium fusion extract, it does not lead to the formation of prussian blue with FeSO4 and Na4[Fe(CN)6]. Instead, it would produce thiocyanate, which does not give a prussian blue color but a red coloration after further reaction with an acidic iron(III) solution.
Conclusion: Statement I is true but Statement II is false.
The monomer (X) involved in the synthesis of Nylon 6,6 gives positive carbylamine test. If 10 moles of X are analyzed using Dumas method, the amount (in grams) of nitrogen gas evolved is ____. Use: Atomic mass of N (in amu) = 14
The correct match of the group reagents in List-I for precipitating the metal ion given in List-II from solutions is:
List-I | List-II |
---|---|
(P) Passing H2S in the presence of NH4OH | (1) Cu2+ |
(Q) (NH4)2CO3 in the presence of NH4OH | (2) Al3+ |
(R) NH4OH in the presence of NH4Cl | (3) Mn2+ |
(S) Passing H2S in the presence of dilute HCl | (4) Ba2+ (5) Mg2+ |
Match List I with List II:
Choose the correct answer from the options given below:
For the thermal decomposition of \( N_2O_5(g) \) at constant volume, the following table can be formed, for the reaction mentioned below: \[ 2 N_2O_5(g) \rightarrow 2 N_2O_4(g) + O_2(g) \] Given: Rate constant for the reaction is \( 4.606 \times 10^{-2} \text{ s}^{-1} \).
Let \( T_r \) be the \( r^{\text{th}} \) term of an A.P. If for some \( m \), \( T_m = \dfrac{1}{25} \), \( T_{25} = \dfrac{1}{20} \), and \( \displaystyle\sum_{r=1}^{25} T_r = 13 \), then \( 5m \displaystyle\sum_{r=m}^{2m} T_r \) is equal to: