The formula for escape velocity is: \[ v_e = \sqrt{\frac{2GM}{R}}, \] where \( G \) is the gravitational constant, \( M \) is the mass of the planet, and \( R \) is the radius of the planet. From the formula, it is clear that \( v_e \propto \sqrt{\frac{M}{R}} \). - As the ratio \( \frac{M}{R} \) increases, the escape velocity \( v_e \) increases. Hence, Statement I is correct.
- However, \( v_e \) depends on \( R \) as seen from the formula, so escape velocity is not independent of the radius of the planet.
Hence, Statement II is incorrect. Thus, the correct answer is \( \boxed{(3)} \).
Match the LIST-I with LIST-II for an isothermal process of an ideal gas system. 
Choose the correct answer from the options given below:
Which one of the following graphs accurately represents the plot of partial pressure of CS₂ vs its mole fraction in a mixture of acetone and CS₂ at constant temperature?
