Solution:
Statement I: Boron is extremely hard indicating its high lattice energy.
Boron forms a giant covalent structure rather than an ionic lattice. Its hardness is due to its strong covalent network, not high lattice energy. Therefore, Statement I is incorrect.
Statement II: Boron has the highest melting and boiling point compared to its other group members.
Boron has a very high melting and boiling point due to its strong covalent network structure. This is true compared to the other group 13 elements. Therefore, Statement II is correct.
Therefore, Statement I is incorrect but Statement II is correct.
Correct Answer: (1) Statement I is incorrect but Statement II is correct
A hydrogen atom consists of an electron revolving in a circular orbit of radius r with certain velocity v around a proton located at the nucleus of the atom. The electrostatic force of attraction between the revolving electron and the proton provides the requisite centripetal force to keep it in the orbit. According to Bohr’s model, an electron can revolve only in certain stable orbits. The angular momentum of the electron in these orbits is some integral multiple of \(\frac{h}{2π}\), where h is the Planck’s constant.
Ion | Q4+ | Xb+ | Yc+ | Zd+ |
---|---|---|---|---|
Radius (pm) | 53 | 66 | 40 | 100 |
Q4+, Xb+, Yc+, Zd+ are respectively