Step 1: Analyze Statement I. The velocity \( \vec{v} \) is given by: \[ \vec{v} = \frac{d\vec{s}}{dt}. \] Integrating both sides with respect to time: \[ \int d\vec{s} = \int \vec{v} \, dt. \] The area under the velocity-time (\( \vec{v} \)-\( t \)) graph gives displacement. Hence, Statement I is true.
Step 2: Analyze Statement II. The acceleration \( \vec{a} \) is given by: \[ \vec{a} = \frac{d\vec{v}}{dt}. \] Integrating both sides with respect to time: \[ \int d\vec{v} = \int \vec{a} \, dt. \] The area under the acceleration-time (\( \vec{a} \)-\( t \)) graph gives the change in velocity. Hence, Statement II is also true.
Final Answer: Both statements are: \[ \boxed{\text{True.}} \]