A wheel of a bullock cart is rolling on a level road, as shown in the figure below. If its linear speed is v in the direction shown, which one of the following options is correct (P and Q are any highest and lowest points on the wheel, respectively) ?
Step 1: Understand Rolling Motion
In rolling motion, a point on the rim of the wheel has both rotational and translational motion. The velocities due to both these motions add vectorially.
Step 2: Analyze the Velocity at Points P and Q
Point P is at the top of the wheel. Its velocity is the sum of the linear speed (v) of the wheel and the rotational speed (v).
Point Q is at the bottom of the wheel, where the linear speed (v) and rotational speed (-v) cancel out.
Step 3: Calculate Velocities
Velocity at P:
$$ v_P = v + v = 2v $$
Velocity at Q:
$$ v_Q = v - v = 0 $$
Step 4: Conclusion
Point P moves faster than Point Q, and Point Q has zero velocity.
The velocity (v) - time (t) plot of the motion of a body is shown below :
The acceleration (a) - time(t) graph that best suits this motion is :
A body of mass 1000 kg is moving horizontally with a velocity of 6 m/s. If 200 kg extra mass is added, the final velocity (in m/s) is:
Consider a water tank shown in the figure. It has one wall at \(x = L\) and can be taken to be very wide in the z direction. When filled with a liquid of surface tension \(S\) and density \( \rho \), the liquid surface makes angle \( \theta_0 \) (\( \theta_0 < < 1 \)) with the x-axis at \(x = L\). If \(y(x)\) is the height of the surface then the equation for \(y(x)\) is: (take \(g\) as the acceleration due to gravity)
A constant voltage of 50 V is maintained between the points A and B of the circuit shown in the figure. The current through the branch CD of the circuit is :