The velocity of a point on a rolling wheel is the vector sum of the linear velocity of the
wheel's center and the tangential velocity of the point due to rotation.
For the topmost point $P$, the tangential velocity due to rotation is in the same direction as the linear velocity.
Thus, its speed is $v + v = 2v$.
For the bottommost point $Q$, the tangential velocity is opposite to the linear velocity, resulting in a net speed of $v - v = 0$.
Thus, point $P$ moves faster than point $Q$.
In rolling motion, a point on the rim of the wheel has both rotational and translational motion. The velocities due to both these motions add vectorially.
Velocity at P:
$$ v_P = v + v = 2v $$
Velocity at Q:
$$ v_Q = v - v = 0 $$
Point P moves faster than Point Q, and Point Q has zero velocity.
A body of mass 1000 kg is moving horizontally with a velocity of 6 m/s. If 200 kg extra mass is added, the final velocity (in m/s) is:
Consider a series of steps as shown. A ball is thrown from 0. Find the minimum speed to directly jump to 5th step